Let $P, Q$ and $R$ be three atomic propositional assertions. Let $X$ denote $( P ∨ Q ) → R$ and Y denote $(P → R) ∨ (Q → R).$ Which one of the following is a tautology?
A→B is implication and B→ A is the reverse implication, in the same way, u can check that...
$X\equiv (\lnot P \wedge \lnot Q)\vee R$
$Y\equiv(\lnot P\vee R)∨(\lnot Q\vee R)$
How $X \equiv Y$ gives always true?
It is not possible to $X \equiv Y$ gives always true(Tautology).
There is one more problem. Ppl who have...