option C. ∃(y)∀(x)[teacher(x)→[student(y)∧likes(y,x)]]
There is a student y for which every x, if x is a teacher then student y likes teacher x.
option D. ∀(x)[teacher(x)∧∃(y)[student(y)→likes(y,x)]]
For every teacher x and some y, if y is a student then he likes teacher x.