Maximum File Size

Question

I am getting 282. Answer given is 256..??

Comments

 Max possible file size = (10 + 16 + 16²) * 2¹⁰ B = 282 * 2¹⁰ B =  282 KB  

Answer 1

282 should be answer.

adresses in a block = 1024/64 = 16 = x

(10+x+x^2) KB = 282KB

Answer 2

Yes..Answer should be 256 only.

Maximum file size=(1024B/64B)²*1024B=2⁸*1024B=256KB.

Comments

^have u any reference  for this concept ?
why 2 include only double

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I have actually studied it in ME.

But I can tell you that generally 2 questions are there.

To calculate Maximum file size and total file size. Just see those questions. It will be enough.

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see this
https://gateoverflow.in/96795/doubt-regarding-unix-i-node-file-system-implementation

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For shortcut just remember that for maximum file size we only consider highest indirect pointer. If here it would have been then we would have used 3.And the concept is like this.Memory is divided into disk blocks. Disk block may have data or pointers to another disk block.

So, double indirect block is like having a block having pointers to blocks.These blocks also have pointers to othere blocks. And these last blocks have data.So, we will add all these blocks.

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@Lucky Why have you not included direct and single indirect in calculation? I think it should be 282 KB.

SImilar gate question - https://gateoverflow.in/2149/gate2012_41

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Yes it should be 282 KB.

Asked in 2012 they included all pointers..

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no..direct and single will not be included. They will be included if we have to calculate total file size.

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@Lucky

Here maximum possible file size is asked , so direct and single , double  will  be included.

But what you calculated above is only maximum file size , which contain only highest indirect pointer. Not all pointers..

Hope you get it.

Correct answer is 282 .