2 votes 2 votes I am getting 282. Answer given is 256..?? Ashwani Kumar 2 asked Feb 7, 2017 Ashwani Kumar 2 1.7k views answer comment Share Follow See 1 comment See all 1 1 comment reply Bikram commented Sep 7, 2017 reply Follow Share Max possible file size = (10 + 16 + 162) * 210 B = 282 * 210 B = 282 KB 0 votes 0 votes Please log in or register to add a comment.
Best answer 1 votes 1 votes 282 should be answer. adresses in a block = 1024/64 = 16 = x (10+x+x^2) KB = 282KB Ravi_1511 answered Feb 7, 2017 • selected Sep 7, 2017 by Bikram Ravi_1511 comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Yes..Answer should be 256 only. Maximum file size=(1024B/64B)2*1024B=28*1024B=256KB. Lucky sunda answered Feb 7, 2017 Lucky sunda comment Share Follow See all 8 Comments See all 8 8 Comments reply Show 5 previous comments Ashwani Kumar 2 commented Feb 7, 2017 reply Follow Share Yes it should be 282 KB. Asked in 2012 they included all pointers.. 1 votes 1 votes Lucky sunda commented Feb 8, 2017 reply Follow Share no..direct and single will not be included. They will be included if we have to calculate total file size. 0 votes 0 votes Bikram commented Sep 7, 2017 i edited by Bikram Sep 7, 2017 reply Follow Share @Lucky Here maximum possible file size is asked , so direct and single , double will be included. But what you calculated above is only maximum file size , which contain only highest indirect pointer. Not all pointers.. Hope you get it. Correct answer is 282 . 0 votes 0 votes Please log in or register to add a comment.