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Consider a two-level cache hierarchy with $L1$ and $L2$ caches. An application incurs $1.4$ memory accesses per instruction on average. For this application, the miss rate of $L1$ cache is $0.1$; the $L2$ cache experiences, on average, $7$ misses per $1000$ instructions. The miss rate of $L2$ expressed correct to two decimal places is ________.
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total number of memory reference = 1000 * 1.4 = 1400

so there are 7 misses for 1400 so misses for 100 = 700/1400 = 0.5

No need to multiply it with 0.1 because in question they asked miss rate of L2 only not combine.

 

So answer is 0.5
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