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Let $u$ and $v$ be two vectors in $\mathbf{R}^{2}$ whose Euclidean norms satisfy $\left \| u \right \| = 2\left \| v \right \|$. What is the value of $\alpha$ such that $w = u + \alpha v$ bisects the angle between $u$ and $v$?

  1. $2$
  2. $\frac{1}{2}$
  3. $1$
  4. $\frac{ -1}{2}$
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Statement :- If a and b be two vectors of equal length, then vector a+b will bisect the angle between a and b.

Proof : 

Here OBCA is a parallelogram. Consider triangle OAC and OBC, they both are congruent to each other (OA=OB, because vector a and b are of equal length ; AC=BC ; OC is common between them). So, angle AOC = angle BOC. Therefore we can conclude that OC bisects angle AOB. Hence Proved.

 

Since ||u|| = 2*||v|| and vector w bisects the angle between u & v. So, w must be u+2v. Therefore $\alpha$=2.

Answer:

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