$\{0,128,256,128,0,128,256,128,1,129,257,129,1,129,257,129\}$
1$^{\text{st}}$ Iteration:
For $\left \{ 0,128,256,128,0,128,256,128 \right \}$
\begin{array}{|l|c|l|} \hline \textbf {Block ID} \ & \textbf{Type} & \textbf{Set 0 content } \\\hline \text{0} & \text{Compulsory Miss} & \text{0} \\\hline\text{128} & \text{Compulsory Miss} & \text{0 128} \\\hline \text{256} & \text{Compulsory Miss} & \text{128 256}\\\hline \text{128} & \text{Hit} & \text{256 128} \\\hline \text{0} & \text{Conflict miss} & \text{128 0} \\\hline \text{128} & \text{Hit} & \text{0 128} \\\hline \text{256} & \text{Conflict miss} & \text{128 256} \\\hline \text{128} & \text{Hit} & \text{256 128} \\\hline \end{array}
Total number of conflict misses $=2$;
Similarly for $\left \{ 1,129,257,129,1,129,257,129 \right \}$, total number of conflict misses in $\text{set1} = 2$
Total number of conflict misses in $1^{\text{st}}$ iteration $= 2+2=4$
$2^{\text{nd}}$ iteration:
for $\left \{ 0,128,256,128,0,128,256,128 \right \}$
\begin{array}{|l|c|l|} \hline \textbf {Block ID} \ & \textbf{Type} & \textbf{Set 0 content } \\\hline \text{0} & \text{Conflict Miss} & \text{128 0} \\\hline\text{128} & \text{Hit} & \text{0 128} \\\hline \text{256} & \text{Conflict miss} & \text{128 256}\\\hline \text{128} & \text{Hit} & \text{256 128} \\\hline \text{0} & \text{Conflict miss} & \text{128 0} \\\hline \text{128} & \text{Hit} & \text{0 128} \\\hline \text{256} & \text{Conflict miss} & \text{128 256} \\\hline \text{128} & \text{Hit} & \text{256 128} \\\hline \end{array}
Total number of conflict misses $= 4$.
Similarly for $\{1,129,257,129,1,129,257,129\}$, total number of conflict misses in $\text{set1} = 4$
Total Number of conflict misses in $2^{\text{nd}}$ iteration $= 4+4=8$
Note that content of each set is same, before and after $2^{\text{nd}}$ iteration. Therefore each of the remaining iterations will also have $8$ conflict misses.
Therefore, overall conflict misses $= 4+8\ast 9 = 76$