0 votes 0 votes Prove or disprove: $\begin{align*} \log_8x = \frac{1}{2}.\log_{2}x \end{align*}$. Set Theory & Algebra discrete-mathematics descriptive non-gate + – dd asked Feb 25, 2017 edited Feb 25, 2017 by dd dd 498 views answer comment Share Follow See 1 comment See all 1 1 comment reply Xylene commented Feb 25, 2017 reply Follow Share log8x = log2x/log28 = 1/3 *log2x . Am I missing something or this is what you asked? 1 votes 1 votes Please log in or register to add a comment.
Best answer 4 votes 4 votes $\log_{8}x=\frac{1}{\log_{x}8} =\frac{1}{3\log_{x}2}=\frac{1}{3}\log_{2}x$ $\log_{8}x\neq \frac{1}{2}\log_{2}x$ srestha answered Feb 25, 2017 selected Feb 25, 2017 by dd srestha comment Share Follow See all 2 Comments See all 2 2 Comments reply Devshree Dubey commented Feb 25, 2017 reply Follow Share @Srestha, which log property have you applied? How could you interchange the base x with tat of 8? Please specify. :). Thanx in advance as well. :) 0 votes 0 votes srestha commented Feb 25, 2017 reply Follow Share $\log _{y}x=\frac{1}{\log _{x}y}$ 1 votes 1 votes Please log in or register to add a comment.
1 votes 1 votes log8x = log2x/log28 = 1/3 *log2x . Am I missing something or this is what you asked? Xylene answered Feb 25, 2017 reshown Feb 25, 2017 by Xylene Xylene comment Share Follow See all 0 reply Please log in or register to add a comment.