0 votes 0 votes The value of x at which y has a minimum for $y = x^2 -3x + 1$ is a. -3/2 b. 3/2 c. 0 d. None of these Linear Algebra isro-ece isro2011-ece engineering-mathematics linear-algebra + – sh!va asked Feb 28, 2017 • retagged Mar 10, 2019 by Naveen Kumar 3 sh!va 398 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes The given equation is an upward parabola. So the minimum value of y exists at the bottommost point of the graph, where the slope is zero. So differentiating the given equation w.r.t x and equating it to zero will give you the answer. dy/dx = 0 2 * x - 3 = 0 ; x = 3/2. Rohit Ranjan answered Feb 28, 2017 Rohit Ranjan comment Share Follow See all 0 reply Please log in or register to add a comment.