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The value of determinant is:

a) 0

b) 1

c) 3

d) a+b+c

in Linear Algebra by Boss (32.3k points)
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+1
ans will be zero perform  C2+C3 then C2 will become  a+b+c  then perform R1-R2 , R2-R3

1 Answer

+3 votes
Perform C2<-- C2+ C3 then take a+b+c common from second column. Now we have two columns C1 and C2 having all entries as 1 so they are linearly dependent so determinant is (a+b+c)( 0 ) which gives answer as 0 (option A)
by Boss (11k points)
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