0 votes 0 votes The value of determinant is: a) 0 b) 1 c) 3 d) a+b+c Linear Algebra isro-ece engineering-mathematics linear-algebra + – sh!va asked Mar 3, 2017 retagged Mar 9, 2019 by Naveen Kumar 3 sh!va 458 views answer comment Share Follow See 1 comment See all 1 1 comment reply Meenakshi Sharma commented Mar 3, 2017 reply Follow Share ans will be zero perform C2+C3 then C2 will become a+b+c then perform R1-R2 , R2-R3 1 votes 1 votes Please log in or register to add a comment.
3 votes 3 votes Perform C2<-- C2+ C3 then take a+b+c common from second column. Now we have two columns C1 and C2 having all entries as 1 so they are linearly dependent so determinant is (a+b+c)( 0 ) which gives answer as 0 (option A) Rahul Jain25 answered Mar 3, 2017 Rahul Jain25 comment Share Follow See all 0 reply Please log in or register to add a comment.