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Consider the following Boolean function of four variables:

$$f(w, x, y, z) = \Sigma(1, 3, 4, 6, 9, 11, 12, 14)$$

The function is

  1. independent of one variables.

  2. independent of two variables.

  3. independent of three variables.

  4. dependent on all variables

asked in Digital Logic by Veteran (59.9k points) | 874 views

1 Answer

+13 votes
Best answer

The K-map would be

  w'x' w'x wx wx'
y'z'   1 1  
y'z 1     1
yz 1     1
yz'   1 1  

So, the minimized expression would be 

x'z + xz'. 

So, option B. 

answered by Veteran (384k points)
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$x \oplus z$
Answer:

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