0 votes 0 votes Vector a= 3i + 2j - 6k, vector b= 4i - 3j + k, angle between above vectors is (a) 90° (b) 0° (c) 45° (d) 60° Linear Algebra engineering-mathematics isro-mech linear-algebra + – sh!va asked Mar 8, 2017 • retagged Mar 7, 2019 by Naveen Kumar 3 sh!va 409 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 3 votes 3 votes Angle between $2$ vectors is given by :- $Cos \ \alpha = \frac{ {\displaystyle {\vec {a}}}. {\displaystyle {\vec {b}}}}{|| {\displaystyle {\vec {a}}}||.|| {\displaystyle {\vec {b}}}||}$ $Cos \ \alpha = 0 \Rightarrow \alpha = 90$ Kapil answered Mar 8, 2017 • selected Mar 8, 2017 by Samujjal Das Kapil comment Share Follow See all 0 reply Please log in or register to add a comment.