The minimum number of edges a connected graph with n vertices will have is (n-1) . Now if we remove any of the edges,this graph will become disonnected.But they have given initailly the graph is connected.So our graph cannot have less than (n-1) edges.
Incase if we have more than (n-1) edges,then removing ANY EDGE from the graph will not guarantee disconnectivity,eventhough removal of some edges may guarantee disconnectivity.So our graph cannot have more than (n-1) edges.
If a graph has multi-edges,then removal of any edge willnot guarantee disconnectivity,beacuse among the 2 vertives which has parallel edges,if i remove one of them other edges will ensure connectivity.So our graph cannot have multi-edges.
Similiarly,if my graph has self-loop,then removal of that self-loop edge will not make the connected graph disconnected.So our graph cannot have self-loops.
If our graph doesnot have multi-edges and self-loops,then it is definitely a simple-graph.