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Put $tany = t$

and by differentiating both sides we get,

$sec^2y dy= dt$ --------(1)

Now put (1) in the given differential euation,

$\frac{\mathrm{d} t}{\mathrm{d} x} + x*t = x^{3}$              --------------> Linear Differential Equation

Integrating factor => IF=$e^{\int xdx}$ = $e^{\tfrac{x^2}{2}}$

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