1 votes 1 votes If a vertex of a triangle is (1, 1) and the mid-points of two sides through this vertex are (-1, 2) and (3, 2), then the centroid of the triangle is (A) $(-1, 7/3)$ (B) $(-1/3, 7/3)$ (C) $(1, 7/3)$ (D) $(1/3, 7/3)$ Linear Algebra engineering-mathematics isro-ee + – sh!va asked Mar 10, 2017 • edited Mar 7, 2019 by Naveen Kumar 3 sh!va 865 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes Let Co-ordinate of vertices be ABC given A(1,1) and mid point of AB & AC are (-1,2) & (3,2) respectively. Mid point AB =(Xa + Xb)/2,(Ya + Yb)/2 hence -1=1+Xb /2 & 2=1+Yb /2 B(-3,3) similarly C(5,3) centroid of Triangle is C(X,Y)= Xa+Xb+Xc/3, Ya+Yb+Yc/3 C(X,Y)=(1,7/3) option C Tesla! answered Mar 10, 2017 Tesla! comment Share Follow See 1 comment See all 1 1 comment reply Sri Sruthi commented Oct 23, 2018 reply Follow Share Great work 0 votes 0 votes Please log in or register to add a comment.