please explain

Question

Answer 1

FOR DMA TRANSFER 

15 cycles for initialization +200 cycles for 100 bytes transfer=215 cycles 

FOR INTERRUPT PROGRAM

consists of 5 instruction each inst takes 1 cycle after they say program will be executed for each byte transfer so for 100 BYTES TRANSFER PROGRAM SHOULD RUN 100 TIMES as now PROGRAM CONSISTS of 5 instruction therefore require total of 500 cycles to transfer 100 BYTES.

SPEED UP=500/215=2.32

Comments

why for DMA only 100 byte are transfer(only one instruction data) while for interrupt 500 byte(five instruction data) are transfer

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@ Manoj_Kumar

why for DMA only 100-byte transfers (only one instruction data) while for interrupt 500 bytes (five instruction data) are transfer

Because Interrupt driven i/o mechanism is based on totally interrupts, in the sense whenever data got ready by I/O device, device will generate interrupts and for generating interrupts, it has to execute ISR and lot of overheads occurs.

Answer 2

Answer will be 2.3255(approx)

For Pipeline

--------------------------------------

15 (initialization) + 100 *2 (as for each byte we take 2 cycles) = 215 cycles

 

For Non Pipeline

-------------------------------------

100*5*(1 cycle) (as for each byte 5 instructions are executed) = 500

 

Speed up = 500/215 = 2.3255(approx)