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An ISP is granted a block of addresses starting with 195.200.0.0/16 (65,536 addresses).

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An ISP is granted a block of addresses starting with 195.200.0.0/16 (65,536 addresses). The ISP 
needs to distribute these addresses to three groups of customers as follows: 


a. The first group has 64 customers; each needs 128 addresses. 


b. The second group has 128 customers; each needs 64 addresses. 


c. The third group has 128 customers; each needs 32 addresses. 

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a)128 IP addresses = $2^{7} = 2^{32-25} = 2^{32-n}$

n=25

1st Group : 1st customer : 195.200.0.0/25 to 195.200.0.127/25

                 2nd customer : 195.200.1.128/25 to 195.200.1.255/25

                 64th customer : 195.200.32.128/25 to 195.200.32.255/25

b)64 IP addresses = $2^{6} = 2^{32-26} = 2^{32-n}$

n=26

2nd Group : 1st customer : 195.200.33.0/26 to 195.200.33.63/26

                  2nd customer : 195.200.33.64/26 to 195.200.33.127/26

                  3rd customer : 195.200.33.128/26 to 195.200.33.191/26

                  4th customer : 195.200.33.192/26 to 195.200.33.255/26

                 128th customer : 195.200.64.192/26 to 195.200.64.255/26

c)32 IP addresses = $2^{5} = 2^{32-27} = 2^{32-n}$

n=27

3rd Group :1st customer : 195.200.65.0/27 to 195.200.65.31/27

                2nd                 195.200.65.32/27 to 195.200.65.63/27

                3rd                  195.200.65.64/27 to 195.200.65.95/27

                4th                  195.200.65.96/27 to 195.200.65.127/27

                5th                  195.200.65.128/27 to 195.200.65.159/27

                6th                  195.200.65.160/27 to 195.200.65.191/27

                7th                  195.200.65.192/27 to 195.200.65.223/27

                8th                  195.200.65.224/27 to 195.200.65.255/27

               128th                195.200.80.224/27 to 195.200.80.255/27
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