Question

Suppose the spectrum of a channel is between 5 Mhz and 6 MHz.If the Signal to Noise ratio is found to be 24 Db , find maximum channel capacity .

Also find maximum number of signal levels in transmitted signal?

Comments

somebody please tell this please ??

Answer 1

Shanon capacity

where C is channel capacity

B is bandwidth

S/N is signal to noise ratio

here B=6-5=1MHZ

C=log(1+24)=4.64Mbps

The shanon capacity gives us the upper limit and nyquist theorem helps us to find number of signal levels

for better performance we choose something lower capacity since higher is 4.64 we take 4Mbps 

C=2*B* log L base2

4=2*1*logLbase2

​​​​​​​so L=4

where L is number of signal levels

Comments

no mam this is wrong

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Please correct me.

According to me when signal to noise ratio is given shanon capacity is used.

to find number of levels nyquist is used

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you need to convert db value into logarithmic value and then put in formula

although the answer is coming rigght