D is the false statement.
A minimum spanning tree must have the edge with the smallest weight (In Kruskal's algorithm we start from the smallest weight edge). So, C is TRUE.
If e is not part of a minimum spanning tree, then all edges which are part of a cycle with e, must have weight $\leq e$, as otherwise we can interchange that edge with $e$ and get another minimum spanning tree of lower weight. So, B and A are also TRUE.
D is false because, suppose a cycle is there with all edges having the same minimum weight $w$. Now, any one of them can be avoided in any minimum spanning tree.