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closed with the note: Undefined Behaviour
explain the output

#include <stdio.h>
int main()
{
 
    int a=1;
    printf("%d %d %d",a,a++,--a);
     return 0;
     
 }
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1 Answer

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These kinds of expressions are compiler dependent....

 printf("%d %d %d",a,a++,a--);

 printf("%d %d %d",a,a++,--a);

Both will give some output which will be 1 0 1

It might be possibility if we run these statement in different compilers, these may give different output...

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