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In a token ring network the transmission speed is 10$^7$ bps and the propagation speed is 200 meters/$\mu$s. The 1-bit delay in this network is equivalent to:

  1. 500 meters of cable.

  2. 200 meters of cable.

  3. 20 meters of cable.

  4. 50 meters of cable.

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2 Answers

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As, token ring network

  So,        transmission delay = length / bandwidth

                  transmission delay = 1/10^7 = 0.1micro sec.

   as,  propagation speed =200m/micro sec.

         In , 1micro sec.  it covers 200m

  than in 0.1micro sec. it is 20metres.(C) answer 

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Can it be solve using, d<= L/2*V/B and by playing with units?
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i have the same doubt as @smartmeet. i tried using formula but couldn't approach. Anyone can help?
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ans c)
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Answer:

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