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+4 votes

In a token ring network the transmission speed is 10$^7$ bps and the propagation speed is 200 meters/$\mu$s. The 1-bit delay in this network is equivalent to:


  1. 500 meters of cable.

  2. 200 meters of cable.

  3. 20 meters of cable.

  4. 50 meters of cable.



asked in Computer Networks by Veteran (69k points)
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2 Answers

+14 votes
Best answer

As, token ring network

  So,        transmission delay = length / bandwidth

                  transmission delay = 1/10^7 = 0.1micro sec.

   as,  propagation speed =200m/micro sec.

         In , 1micro sec.  it covers 200m

  than in 0.1micro sec. it is 20metres.(C) answer 

answered by Loyal (3.7k points)
selected by
Can it be solve using, d<= L/2*V/B and by playing with units?
i have the same doubt as @smartmeet. i tried using formula but couldn't approach. Anyone can help?
0 votes
ans c)
answered by Boss (5.1k points)

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