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The message 11001001 is to be transmitted using the CRC polynomial $x^3 +1$ to protect it from errors. The message that should be transmitted is:

1. 11001001000

2. 11001001011

3. 11001010

4. 110010010011

+10

CRC Calculation

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How come 1100-1001 is 101? Should it not be 11?

degree of generator polynomial is 3 hence 3 bits are appended before performing division

after performing division using 2's complement arithmetic remainder is 011

the remainder is appended to original data bits

By Anurag Pandey

edited
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m + r + 1 < 2r

messege, m = 8 bits

8 + 1 + 1 > 21

8 + 2 + 1 > 22

8 + 3 + 1 > 23

8 + 4 + 1 < 24

Hence r = 4

then sending mesg is 8 + 4 = 12 bits

ANS : d

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This is for hamming code.
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In the end you appended 011 and not 0011, why like that?
110011 011 where 011 is crc
Answer is d the no. Of bits u add for n degree poly is n+ 1
ans a)
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Can you please give detailed explanation?
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seriously she does nt explain anything....
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how are you xoring 1011 with 1001 such that you are taking in the next step 1001?