Modified form of gate - 2000 , ISRO 2015

Question

#include<stdio.h>
struct 
{
    short x[5];
    union 
    {
        float y;
        long z;
    }u;
}t;
int main() 
{
    printf("short=%d\n",sizeof(short));
    printf("float=%d\n",sizeof(float));
    printf("long=%d\n",sizeof(long));
    printf("%d",sizeof(t));
    return 0;
}

Answer should be 14 but why the answer is 16 ?

Note : short : 2 bytes , float : 4 bytes , long : 4 bytes

Answer 1

Please verify the question before posting it.

Its a basic question in which they only want to know if candidate knows the UNION storage allocation rule or not.

14 is correct answer for your question while in original question they mentioned long size 8 bytes and hence answer was 18 bytes correspondingly.

2*5+8=18 bytes

Comments

Please see the below screenshot - 

 

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I'm sorry that i ignored one point.

you're getting it 16 because of alignment or padding . but you won't have to worry about this. No one will consider alignment during exam.

https://en.wikipedia.org/wiki/Data_structure_alignment

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Correct!! That is why I asked the question to know what is alignment and padding ? And whether it is necessary or not ?