How to find address of an element in array in Binary

Question

Let's say we have an array of 5 elements.

Array index starts from 0 

Base address of Array = 100 

size of each element is 2 ie it's an int array

Now we want to find the 2nd element ie A[2]. 

So, the procedure is like - 

A[2] = Base address + (index*size of each element in memory)

A[2] = 100+(2*2)

Now how to find the BOLD text ie address of 2nd element in BINARY?!

Thanks

Comments

100+(2*2) means Base Address of Array + (Skip 2 element (at index 0 and 1) * each has size 2 byte ) 

---

sizeof int is 2?

---

Not given sir ?

Answer 1

i think you can write the code for conversion of decimal to binary because we always get decimal values and the address value is equivalent to the address in binary.

if i am wrong than correct me.