0 votes 0 votes The minimum number of NAND gates required to implement the boolean function A+AB(bar)+AB(bar)C is equal to (a)0 (b)1 (c)4 (d)7 .HOW TO SOLVE SUCH TYPE OF QUESTION? WHAT SHOULD BE THE APPROACH? jatin kumar 3 asked May 2, 2017 jatin kumar 3 5.0k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 2 votes 2 votes First let us simplify the expression : A + AB' + AB'C = A + AB'(1 + C) = A + AB' = A(1 + B') = A So no NAND gate needed in fact.. Hence A) should be the correct answer. Habibkhan answered May 2, 2017 selected May 2, 2017 by Habibkhan Habibkhan comment Share Follow See all 0 reply Please log in or register to add a comment.
2 votes 2 votes A + AB' + AB'C = A( 1+B' ) + AB'C = A +AB'C [ A + 1 = 1 ] = A(1 + B'C) = A So Not need NAND Gates Option (A) is right answer Lakshman Bhaiya answered May 2, 2017 Lakshman Bhaiya comment Share Follow See all 0 reply Please log in or register to add a comment.