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Let X be a length used to make three sides of a rectangle. Area of rectangle will be:

A. $X^{2}/9$

B. $(X-a)^{2}/4$

C. $(X+a)^{2}/16$

D. None of the above
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I feel Option A is correct

We know from properties that square is a type of rectangle with all sides measuring equal in length

So, let us consider length of sides of rectangle = $a$

Now , in the given question, the length of 3 sides of rectangle is given  = X

So we can rewrite it as , $X = 3a$

Now squaring on both sides , we get  

$X^{^{2}} = 9a^{2}$

ie , $X^{^{2}}/9 = a^{2}$ ,

So , we know that area of square (We assume it as an equal side rectangle) =  $a^{2}$

So the answer is Opt (A) = $X^{2}/9$

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