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How many $128\times 8$ bit RAMs are required to design $32K\times 32$ bit RAM?

1. 512
2. 1024
3. 128
4. 32

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Number of RAM = (32 * K * 32) / 128 * 8

= 25 * 210 * 25  /  27 * 23

=220 / 210

= 1024

option B...

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Number of $\text{RAMs}$ required $= \frac{32K \times 32}{128\times 8} = \frac{2^{20}}{2^{10}} = 2^{10} = 1024$
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