0 votes 0 votes In a triangle ABC,sinA.cosB=(1/4) and 3tanA=tanB,then the triangle is? a) right angles b)equilateral c)none of these Angkit asked May 11, 2017 Angkit 1.1k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 1 votes 1 votes 3 tanA =tan B 3 sin A/cos A =sin B/cos B 3 sin A.cos B=cos A.sinB cos A.sin B= 3/4 (becoz sin A.cos B=1/4 ) now sin(A+B) = sinA.cosB+cosA.sinB sin(A+B)=1/4+3/4=1 ie A+B=90 digree so C=90 so right angle triangle pawan kumarln answered May 12, 2017 • selected Aug 13, 2017 by pawan kumarln pawan kumarln comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Right angled triangle Archies09 answered May 11, 2017 Archies09 comment Share Follow See all 0 reply Please log in or register to add a comment.