retagged by
632 views
3 votes
3 votes

The bandwidth of a $TCP$ connection is $1048560$ $bits/s$. Let $a$ be the value of $RTT$ in milliseconds, after which $TCP$ window scale option is required. Let $b$ be the maximum possible window size (with window scale option).

Then, the value of $a$ and $b$ are:

  1.   $63$ and $65535 \times 2^{16}$
  2.   $63$ and $65535 \times 2^{14}$
  3.   $500$ and $65535 \times 2^{16}$
  4.   $500$ and $65535 \times 2^{14}$
retagged by

2 Answers

0 votes
0 votes
tcp is a byte oriented protocol

bandwidth$=$$1048560/8 Bps =131070 Bps$

$rtt$ $=$ $2$^$16 Bytes/131070Bps =500ms$

scaling factor is $2$^$14$ in $tcp$

so max poss window size is $65535*2$^$14$
Answer:

Related questions

0 votes
0 votes
2 answers
1
Bikram asked May 14, 2017
365 views
Which kind of connection between the client and server is opened by $\text{TCP?}$ One-way Symmetric Connection One-way Asymmetric Connection Two-way Symmetric Connection ...
2 votes
2 votes
3 answers
4