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How many 32K $\times$ 1 RAM chips are needed to provide a memory capacity of 256K-bytes?

1. 8
2. 32
3. 64
4. 128

### 1 comment

How did you guess that the 32K x 1 chips has size in bits and not bytes??

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Total number of RAM chips

\begin{align*}&= \frac{\text{Total size}}{\text{1 RAM size}} \\ &=\frac{256 \text{ K-bytes}}{ 32 \times 1} \\ &= \frac{2^8 \times 2^{10} \times 2^3}{ 2^5\times 2^{10}}\\ &= 2^6 = 64 \end{align*}

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87 160 223

moved
C) 64
$32K \times 1$ RAM

Is specifying no unit a new standard? or "$\times 1$" is a new notation for "bits"? Any link / wiki explaining this new notation?
To me "$32K\times 1$ RAM" looks like a printing mistake. How one is supposed to decode it straight that it means 32Kbits without having any doubt?

@GateAspirant999 even I would like to know, whether this is a new standard?

(256K x 8) / (32K x 1) = 64
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40 66 126

total number of RAM chip = Total size /1 RAM size
=256K bytes/ 32*1
= 2210 *23/ 25*210

=  26 = 64
Option C

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36 82 153

You should convert byte to bit.. Answer should be 8 * 8 = 64

oh yah i forgot!

Is there any reason, why should we convert byte into bit?
I am also confused as 32k * 1 should mean 32k addresses each 1 byte, as a system is byte addresable?
Did u get the answer of multiplying by 8

Explanation: We need 256 Kbytes, i.e., 256 x 1024 x 8 bits.
We have RAM chips of capacity 32 Kbits = 32 x 1024 bits.
(256 * 1024 * 8)/(32 * 1024) = 64 chips

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### 1 comment

How can we know that RAM capacity is given in bits or bytes.

They have just written 32k *1

Help....