According to question ,Three different numbers are selected from the set X = {1,2,3,4,…,10}.There are only three possibility where we will get the product of two of the numbers is equal to the third {2,3,6}, {2,4,8}, {2,5,10}.
probability that the product of two of the numbers is equal to the third (p) = number of favorable cases / total cases
= 3 / 10c3 = 3/120 = 1/40 ans