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What is the number of swaps required to sort $n$ elements using selection sort, in the worst case?

  1. $\Theta(n)$

  2. $\Theta(n \log  n)$

  3. $\Theta(n^2)$

  4. $\Theta(n^2 \log  n)$

 

asked in Algorithms by Veteran (69k points)
edited by | 977 views

1 Answer

+21 votes
Best answer

The answer is A.

we have $1$ swap in each loop and hence $n$ swaps at max for $1$ to $n$. Therefore the worst case number of swaps is $\Theta(n)$

answered by Veteran (19.8k points)
edited by
Best case: $0$ swaps. for eg $1,2,3,4,5,6$

Worst case: $n-1$ swaps for eg $6,5,2,1,4,3$

@reena ma'am, it depends on implementation, but in its basic form, even in best case selection sort requires 1 swap in each pass. https://stackoverflow.com/questions/26688765/what-are-the-number-of-swaps-required-in-selection-sort-for-each-case



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