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A box contains five set of balls while there are three balls in each set. Each set of balls
has one colour which is different from every other set. What is the least number of balls that must be
removed from the box in order to claim with certainty that a pair of balls of the same colour has been
removed?
(a) 6 (b) 7
(c) 9 (d) 11

1 Answer

Best answer
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Given:  5 sets and 1 set with 3 balls  

so total balls =15

, and in all the sets only 1 ball is different from others, so 5 balls r different , so we have to pick more than 5.

now we have 10 balls remaining .it has clearly mentioned that only 1 ball in each set is different , means remaining balls have to repeat in any one of the 5 sets.in the worst scenario one ball will repeat at only one place . so again we can pick 5 balls which can  be of different colors. but now,when we pick the 11th ball then one of the pair will be of same color.

ex- red ,green, blue-> set1

    red ,black ,gray->set2

    black ,pink ,purple ->set3

  green,white,yellow->set4

  pink,white,orange->set5

​​​​​​​now in 1 time we have taken blue,gray,purple,yellow  and orange. all r from different sets.

next time we choose red ,black, green ,pink and white now too we r able to pick it with different colors. total balls till now are 10 but when we pick any of the 11th ball it will be of same color .

so answer should be optin .D

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