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Pointer

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Note that: *(*(p + i) + j) and *(*(i + p) + j) is same.
Similarly *(*(j + p) + i) and *(*(p + j) + i) is equivalent.

printf can be rewritten as: printf ("%d %d %d %d", p[i][j], p[j][i], p[i][j], p[j][i])
since *(p + offset) is equivalent to p[offset].

This would print successive values of the array 'a' as i iterates from [0, 2) and

j iterates from [0, 3):
1 1 1 1
2 2 2 2
3 3 3 3
2 2 2 2
3 3 3 3
4 4 4 4

For eg on first iteration of i and j,
it would print 1, 1, 1, 1 since i == 0 and j == 0

When i == 0, and j == 1
p[i][j]
== p[0][1]
== 2
 
and p[j][i]
== p[1][0]
== 2
 
So it would print 2 2 2 2
and so on.
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