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Does the following represents function from R->R ?

f(x)=√x

In ths solution ,it is given:- f(x) is not defined for x < O. 

But do we consider it by default as +/-√x or is it only +√x?

I have asked a similar ques:-https://gateoverflow.in/132553/discrete-maths-group-theory

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2 Answers

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if we consider f(x) = +or - sqrt(x) then it canot be a function because x can not take two different value at same time according to definition of function
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$R \to R$ is mentioned in question meaning the domain and range of $f$ are the set of all real numbers. Now, $f(-2) = \sqrt{-2}$ is not a real number and thus $f$ is no longer a valid function.

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