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A bag contains Red Balls and Black Balls. Two balls are drawn without replacement. The probability that both the balls drawn are red is 1/2. What is the minimum number of Red and Black Balls for which this probability is satisfied?

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I have solved it by trial and error method.

Say 4 balls in the bag.

3 balls are red and 1 is black.

Now probability without replacement =$\frac{3\times 2}{4\times 3}=\frac{1}{2}$
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