Answer will be A.I think in question they will give base adress 2000 and each int takes 4 bytes based on that info I will explain
Here x ={x1,x2,x3,x4} Assuming each inside variable is a one dimension array
x+3 means it points to x3 so before that we have two arrays each with 3 integers so 2000 + 2* 3* 4 + 4(bcz it is pointing x3) = 2036
*(x+3) also same address because it is pointing first integer in X3 array that is x3[0] and we know both x3 and x3[0] address same so 2036.
*(x+2) +3 means first *(x+2) means pointing to x2[0] then we are moving 3 integers(and in x2 we have 3 integers) i.e we are pointing to x3 first integer which is 2036