program

Question

main()
{
int m,row, col;
int *ptr ,sum = 0 ;
  int arr[2][2][2] ={1,2,3,4,5,6,7,8};
 int(*p)[2][2] ;
   p = arr;
  for(m=0;m<2;m++)
1  {
  ptr =  p+m;
  for(row= 0 ;row<2;row=row+2)
   {
   ptr = ptr + row ;

   for(col=0;col<2;col=col+1)
   {
   sum = sum + *(ptr+col);
   }
   }
   }
   printf("%d",sum);

   }

can someone show me with a diagram how it is processing morever , at ptr = p + m  , when control go here  ptr stores 1 , my question is ptr should hold address because its a pointer , thanks

Answer 1

In the line ptr=p+m; there is a need for typecasting as p is a ponter to two dimensional array of size 2*2..and ptr is a pointer to integer..so it should be written as

Ptr=(int*)(p+m);

And for ur question ..indeed ptr will hold the address and initially it is holding the address of first element of three dimensonal array  ...                                    

May b this will help u to solve this ques ..