1 votes 1 votes Please tell how to solve d and e? Mathematical Logic generating-functions combinatory + – rahul sharma 5 asked Jun 18, 2017 • retagged Jun 27, 2017 by Arjun rahul sharma 5 1.2k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
3 votes 3 votes solution for option d: solution for option e: Niraj Singh 2 answered Jun 21, 2017 • edited Jun 21, 2017 by Niraj Singh 2 Niraj Singh 2 comment Share Follow See all 4 Comments See all 4 4 Comments reply Hemant Parihar commented Jun 21, 2017 reply Follow Share For option e, I think there is small mistake. You miss x in the series of $e^{x}$. 0 votes 0 votes Niraj Singh 2 commented Jun 21, 2017 reply Follow Share yes bro, editted..thanks for pointing out 0 votes 0 votes rahul sharma 5 commented Jun 22, 2017 reply Follow Share Thanks a lot :) 0 votes 0 votes bhuv commented Sep 9, 2017 reply Follow Share @rahul sharma 5 I think something is wrong with formula given in the question, there should be $$(a_{n})^{n}$$ I thought so because formula for $$e^{-x} = 1 + \frac{-x}{1!} + \frac{(-x)^{2}}{2!} + \frac{(-x)^{3}}{3!} + ........$$ or is it just some different $a_{n}$ idk? 0 votes 0 votes Please log in or register to add a comment.