As I know that if any schedule is conflict serializable then it must be view serializable but
if not conflict serializability then check for blind write
if not found then not view serializable
if found then check from polygraph
or
If a schedule S is view-equivalent to a serial schedule, we say S is view-serializable.
so how to check for single schedule with three transactions with view-equivalent.if the question given for one schedule with three transaction. then we have to make serial schedule by given schedule or what.
please help if possible with help of diagram or example.