789 views

1 Answer

Best answer
5 votes
5 votes

Let's say N have 3 factors.

1 and N will always be its 2 factors. So only 1 factor is left.

Now we need to take number P having only 1 factor > 1 and < P.

This number P can only be (prime)2.

So total squares of prime < 1000.

eg.

4 = 22 = Factors(1, 2, 4)

9 = 32 = Factors(1, 3, 9)

25 = 52 = Factors(1, 5, 25)

49 = 72 = Factors(1, 7, 49)

...

961 = 312 = Factors(1, 31, 961)

Till 312 are < 1000.

N = (22, 32, 52, 72, 92, 112, 132, 172, 192, 232, 292, 312)

Total numbers < 1000 with exactly 3 factors = 12

selected by

Related questions

2 votes
2 votes
1 answer
1
akankshadewangan24 asked Jun 28, 2017
500 views
how many two digit odd numbers are there with 8 factors?