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if a-b/2 ,b/2 . c-b/2 are in GP then a,b,b are in .............

GP

HP

AP

none

 

explain plz

1 Answer

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According to question  a-b/2 , b/2 , c-b/2 are in GP 

then          (b/2)/ (a-b)/2   =  (c-b)/2 / b/2

                  b/ a-b = c-b / b

                  b2 = a-b  *  c-b

               1/b  =  1/a  +  1/ c 

Hence    a, b , c in  H.P                            ans
 

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