0 votes 0 votes let a1,a2,a3...........a10 be integers such that 0<a1<a2<a3................<a10 if S=a1+a2+a3 +........+a10 then 110<= S<= 55 110<=S 55<=S 55<=S<=110 Verbal Aptitude quantitative-aptitude + – akankshadewangan24 asked Jun 29, 2017 akankshadewangan24 341 views answer comment Share Follow See all 4 Comments See all 4 4 Comments reply joshi_nitish commented Jun 29, 2017 reply Follow Share S>=55...it has no upper bound and can go till infinity... 2 votes 2 votes air1 commented Jun 29, 2017 reply Follow Share Since $0 < a_1 < a_2 < a_3 < ... < a_{10}$, all the 10 integers are unique. What is the minimum possible sum of 10 unique positive integers? 0 votes 0 votes manav kothari commented Jul 7, 2017 reply Follow Share 1 to 10 55 0 votes 0 votes manav kothari commented Jul 7, 2017 reply Follow Share 110<= S<= 55 this line is a mistake 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes According to question , we can let 0<a1<a2<a3................<a10 suppose , let integer 1, 2, 3,4,5,6,7,8,9,10 Smin = 1+2+3+.........+10 = 55 Thus, we can say that S should be greater than equal to 55. S > = 55 Ans Akash Verma 1 answered Nov 12, 2017 Akash Verma 1 comment Share Follow See all 0 reply Please log in or register to add a comment.