The Gateway to Computer Science Excellence
+2 votes

in Linear Algebra by Boss (25.6k points) | 392 views
eigen values will be 2,14... dont know about eigen vector..

1 Answer

0 votes

Answer is A.  2, 14,x1,x2

Correct me if I am Wrong

by Active (4.8k points)
So eigen vector of A^m is same as A and eigen vector of polynomial matrix equation given above will be same as A also?
Yes... you can try for some examples the eigenvector for A turns out to be the same for A^m as well as the equation.
@ Rahul

Yes they are same, see this

$ Ax = \lambda x \\ A^{^{2}}x = AAx = A\lambda x = \lambda Ax= \lambda \lambda x $

$A^{^{2}}x = \lambda^{2}x$
Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true
50,833 questions
57,750 answers
108,161 users