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+2 votes
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in Linear Algebra by Boss (25.2k points) | 350 views
0
eigen values will be 2,14... dont know about eigen vector..

1 Answer

0 votes

Answer is A.  2, 14,x1,x2
 

Correct me if I am Wrong

by Active (4.7k points)
0
So eigen vector of A^m is same as A and eigen vector of polynomial matrix equation given above will be same as A also?
0
Yes... you can try for some examples the eigenvector for A turns out to be the same for A^m as well as the equation.
+1
@ Rahul

Yes they are same, see this

$ Ax = \lambda x \\ A^{^{2}}x = AAx = A\lambda x = \lambda Ax= \lambda \lambda x $

$A^{^{2}}x = \lambda^{2}x$
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