0 votes 0 votes If we solve this we will get total 4 eigen vectors,but as we know that this is of 2 degree matrix so only 2 will exist.So can i say that from these four pairs by using nay 2 ,i can derive the other?If yes,then how? Linear Algebra linear-algebra engineering-mathematics eigen-value + – rahul sharma 5 asked Jul 2, 2017 rahul sharma 5 984 views answer comment Share Follow See all 5 Comments See all 5 5 Comments reply joshi_nitish commented Jul 2, 2017 reply Follow Share answer will be (A)...and why you will get 4 eigen vectors, only 2 eigen vectors corresponding to 2 eigen values....if you are saying in this sense """""one time take x as arbitary next time take y as arbitary""""".....it will not make 4 eigen vector, it is still two eigen vectors, because ultimately you will take out common arbitary... i dont know if you understand what i am saying.. 0 votes 0 votes rahul sharma 5 commented Jul 11, 2017 reply Follow Share Answer is both a and c and it was marks to all 0 votes 0 votes joshi_nitish commented Jul 11, 2017 reply Follow Share how option 'c' could be answer??....in second pair of eigenvector [0 1], it is not possible because here x=0 and since either x or y is linearly dependent on other then other should also be 0... 0 votes 0 votes Shubhanshu commented Jul 19, 2017 reply Follow Share what will be its eigen values and vector please explain 0 votes 0 votes amrendra pal commented Sep 1, 2017 reply Follow Share here , there will be two eigen vectors ({1,-j} corresponding to eigen value i and {j,-1} corresponding value -i). 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes The answer is A ,Since the eigen value is j, and -j finding the corresponding eigen vector, which gives {1 -i} and {i,-1} respectively reno answered Jul 29, 2017 reno comment Share Follow See all 0 reply Please log in or register to add a comment.