orange color text is right but , we can also do it in other way in blue text see , why iam not getting answer

Question

Answer 1

both are correct.and Output -0 (why)

printf("%d",strlen(c+2[p]-6[p]-1));

c=means array address.

2[p]=p[2]=T(element at p[2])

6[p]=p[6]=2(element at p[6])

ASCII value of T is 84 & ASCII value of 2 is 50.

c + 2[p] - 6[p] -1

 =c + 'T' - '2' - 1

= c + 14 - 1

= c + 13

(The C library function size_t strlen(const char *str) computes the length of the string str up to, but not including the terminating null character.)

strlen(c+33)

=0(it point to outside bounds of constant string)

Comments

thnks for replying but my question is :

 suppose

int *p

p = &a ;   , then p will contain address of a

 

but here

char  *p  

p = &c //

p should contain address of c  which is outside block in ur diagram , ,

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why u make complicated..

according to your question

 char *p=c;

here value inside c are assigned to p.according to your question ,

if char *p=&c;

then here address of c assigned to variable p.

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acha acha in my question value inside it will exchange thanks bhai agya got it :)