2 votes 2 votes Howany bits are required to encode all twenty six letters, ten symbols and ten numerals? (a) 5 (b) 6 (c) 7 (d) 46 Also give explanation alokraj1142 asked Jul 5, 2017 alokraj1142 609 views answer comment Share Follow See all 2 Comments See all 2 2 Comments reply sourav. commented Jul 5, 2017 reply Follow Share $6$? 0 votes 0 votes alokraj1142 commented Jul 5, 2017 reply Follow Share but what is the explanation of this question 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes Number of bits required to encode=$\left \lceil log_{2}\,\,26+10+10 \right \rceil=6$ sourav. answered Jul 5, 2017 sourav. comment Share Follow See 1 comment See all 1 1 comment reply Siva Tarun commented Jul 21, 2017 reply Follow Share how it will be, i think in digital logic, alphabets are represented using ascii values, and also in the question , not mentioned whether alphabets are capital or not. to represent a alphabets in ascii we need 7 bits 0 votes 0 votes Please log in or register to add a comment.