2 votes 2 votes The solution says that the answer should be 80, but applying the formula (x/y)*100, where x is 250 and y is 200 fraction comes out to be greater than 1. Am i making a mistake in interpreting x and y here? CO and Architecture co-and-architecture made-easy-test-series interrupts io-handling + – kimaya asked Jul 8, 2017 • edited Mar 5, 2019 by adeebafatima1 kimaya 797 views answer comment Share Follow See 1 comment See all 1 1 comment reply Tuhin Dutta commented Dec 2, 2017 reply Follow Share What % of processor time is consumed by I/O device means % of time CPU is idle. right? Now this is given by: Data transfer time (say y) _______________________________ Data Preparation time(say x) + y Isn't this should be the case? 2 votes 2 votes Please log in or register to add a comment.
6 votes 6 votes Total time = (200+250)us = 450 us. Processor involvement time = 250 us. % of cpu time =(250/450)*100 = 55.56% So ans should be (d). mystylecse answered Jul 19, 2017 mystylecse comment Share Follow See all 0 reply Please log in or register to add a comment.