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explain the output please.

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2 votes
2 votes
int main()
{
   int a = 3, b = -8, c = 2;
   printf("%d", a % b / c);
   return 0;
}
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2 Answers

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"1" is right answer because if you find a modulo division with positive number with negative number then it always return a positive number as modulo division....
in your question ,a%b that means 3%(-8) it returns 3 however you try yourself by changing positive number it always give you same positive number( in the case of only single digit like 1,2,3,4...9) as remainder.
then ,after getting 3 as a remainder you have to divide it by 2,(3/2) it result as integer division and finally give 1 as output....
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1)Precedance of modulo division is more,so a%b/c is equivalent to ((a%b)/c).

2)Modulo division as if 'Mod' word means always +ve.So a%b is always +ve.

So,a%b/c=((|a%b|)/b.int=3,b=-8,c=2.Hence,((|3%-8|)/2)=(3/2)=1.
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